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fix(lang): 修复路径含连字符时无法匹配bundle的问题

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新增尝试原始段名的匹配逻辑，同时支持camelCase、snake_case和原始段名三种命名方式，覆盖更多bundle命名场景
This commit is contained in:
ZF Sun
2026-07-09 16:26:02 +08:00
parent d0a3976cda
commit d4794a7be4
1 changed files with 15 additions and 8 deletions
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23
common/js/lang.js
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@@ -856,26 +856,31 @@ function normalizeRemoteTreeForPage(tree, langPath) {
const segments = String(langPath).split('/').filter(Boolean);
if (!segments.length) return tree;
// 沿 langPath 段向下找页面 leaf:同一段同时尝试 camelCase 与 snake_case(bundle 服务器侧
// 对同一段实际可能用任一种命名,例如 point/order_list 在 bundle 里是 `tree.point.order_list.X`,
// 而 login/login 这种 camel 路径又是 `tree.login.login.X`)。
// 沿 langPath 段向下找页面 leaf:同一段同时尝试 camelCase、snake_case 与原始段名
// (bundle 服务器侧对同一段实际可能用任一种命名,例如 point/order_list 在 bundle 里是
// `tree.point.order_list.X`,而 login/login 这种 camel 路径又是 `tree.login.login.X`;
// 路径含连字符(如 ai-chat/index)时,原始段名 `ai-chat` 是唯一能命中 bundle 的形式)。
let leaf = tree;
let hasLeaf = true;
for (const segment of segments) {
const camel = toCamelCaseName(segment);
const snake = toSnakeCaseName(segment);
// 优先 camelCase;没有就回退 snake_case;都没有就放弃
const raw = segment;
// 优先 camelCase;回退 snake_case;再回退原始段名;都没有就放弃
const key = (leaf && typeof leaf === 'object' && !Array.isArray(leaf) && leaf[camel] !== undefined)
? camel
: (leaf && typeof leaf === 'object' && !Array.isArray(leaf) && leaf[snake] !== undefined
? snake
: null);
: (leaf && typeof leaf === 'object' && !Array.isArray(leaf) && raw !== camel && raw !== snake && leaf[raw] !== undefined
? raw
: null));
if (key === null) { hasLeaf = false; break; }
leaf = leaf[key];
}
const lastSegment = toCamelCaseName(segments[segments.length - 1]);
const lastSegmentSnake = toSnakeCaseName(segments[segments.length - 1]);
const rawLast = segments[segments.length - 1];
const lastSegment = toCamelCaseName(rawLast);
const lastSegmentSnake = toSnakeCaseName(rawLast);
const currentPageLeaf =
hasLeaf && leaf && typeof leaf === 'object' && !Array.isArray(leaf)
? leaf
@@ -883,7 +888,9 @@ function normalizeRemoteTreeForPage(tree, langPath) {
? tree[lastSegment]
: (tree[lastSegmentSnake] && typeof tree[lastSegmentSnake] === 'object' && !Array.isArray(tree[lastSegmentSnake])
? tree[lastSegmentSnake]
: null));
: (rawLast !== lastSegment && rawLast !== lastSegmentSnake && tree[rawLast] && typeof tree[rawLast] === 'object' && !Array.isArray(tree[rawLast])
? tree[rawLast]
: null)));
if (!currentPageLeaf) return tree;